No. 6 Penn State Women’s Soccer To Host Indiana-Michigan Winner In Big Ten ‘Regional Weekend’
The road to the Big Ten Tournament title is set for Penn State women’s soccer.
After winning a regular-season championship, the Nittany Lions will play the winner of Indiana and Michigan on Sunday, April 11, for the Big Ten’s “Regional Weekend.”
One of the many changes to this year’s season due to COVID-19, the Regional Weekend acts as a purgatory between the conference regular season and tournament.
The Big Ten decided to split the conference into its two divisions and reseed the teams. Based on those rankings, the 14 sides have been split into four mini-tournaments for Regional Weekend, with the winners of each heading to the proper Big Ten Tournament the following week.
Indiana and Michigan received the No. 4 and No. 5 spots in the Big Ten East, respectively, meaning that they will play for the right to face No. 1 Penn State. That match will take place in State College on Thursday, April 8, and is a de facto elimination game.
Penn State has played and beaten both of its prospective opponents. On March 4, the Nittany Lions beat the Hoosiers 2-1 after falling behind in the 53rd minute. A few weeks later, Payton Linnehan and Sam Coffey put on a masterclass against Michigan, dispatching the Wolverines 4-1 at Jeffrey Field.
Should Penn State win its Regional Weekend mini-tournament match, the team will also host the Big Ten Tournament due to its No. 1 ranking in the conference. The conference championship will be a four-team event played between April 15 and 18.
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For the second year in a row, the Land Grant Trophy is headed back to State College.
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